0 \Rightarrow 2 \tan x \sec ^{2} x>2 \sec ^{2} x f'(\tan ^{2} x-2 \tan x+4)=f'(3)=0 \Rightarrow \tan x>1 \Rightarrow x \\in(\frac{\\pi}{4}, \frac{\\pi}{2}) ∵ At x=\frac{\\pi}{4} \Rightarrow x>\frac{\\pi}{4}" >

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AP EAPCET 19-Aug-2021 Shift 2 Paper

Section: Mathematics

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Question : 73

Total: 160

If f"(x) is a positive function for all x∈R,f′(3)=0 and g(x)=f(tan2(x)−2‌tan(x)+4) for 0<x<

, then the interval in which g(x) is increasing is

(
π
6
,
π
3
)
(0,
π
4
)
(0,
π
3
)
(
π
4
,
π
2
)

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