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AP EAPCET 19th May 2023 Shift 1 Solved Paper

Question : 4

Total: 160

If A=[

2	1	3	−1
1	−2	2	−3

2	1	0	3
1	−1	2	3

] and 2A+3B−5C=0, then C=

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2	1	6∕5	7∕5
1	7∕5	2	3∕5

−2	1	6∕5	7∕5
1	−7∕5	2	3∕5

−2	1	6∕5	7∕5
1	7∕5	2	3∕5

2	1	6∕5	7∕5
1	−7∕5	2	3∕5