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AP EAPCET 20-Aug-2021 Shift 1 Paper
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© examsnet.com
Question : 19
Total: 160
Given
3
x
−
2
(
x
+
1
)
2
(
x
+
3
)
=
A
x
+
1
+
B
(
x
+
1
)
2
+
C
x
+
3
then
4
A
+
2
B
+
4
C
5
-5
-3
3
Validate
Solution:
3
x
−
2
(
x
+
1
)
2
(
x
+
3
)
=
A
x
+
1
+
B
(
x
+
1
)
2
+
C
x
+
3
⇒
3
x
−
2
=
A
(
x
+
1
)
(
x
+
3
)
+
B
(
x
+
3
)
+
C
(
x
+
1
)
2
Putting
x
=
−
1
−
5
=
2
B
⇒
B
=
−
5
2
Putting
x
=
−
3
−
11
=
4
C
⇒
C
=
−
11
4
Putting
x
=
0
−
2
=
3
A
+
3
B
+
C
⇒
−
2
=
3
A
−
15
2
−
11
4
⇒
33
4
=
3
A
⇒
A
=
11
4
⇒
4
A
+
2
B
+
4
C
=
11
−
5
−
11
=
−
5
© examsnet.com
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