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Test Index
AP EAPCET 20-Aug-2021 Shift 1 Paper
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© examsnet.com
Question : 51
Total: 160
Find the equation of the circle which passes through origin and cuts off the intercepts
−
2
and 3 over the
x
and
y
axes respectively.
x
2
+
y
2
−
2
x
+
8
y
=
0
2
(
x
2
+
y
2
)
+
2
x
−
3
y
=
0
x
2
+
y
2
−
2
x
−
8
y
=
0
x
2
+
y
2
+
2
x
−
3
y
=
0
Validate
Solution:
2
√
g
2
−
c
=
2
2
√
f
2
−
c
=
3
and
c
=
0
g
=
±
1
,
f
=
±
3
2
x
2
+
y
2
±
2
x
±
3
y
=
0
It passes through
(
−
2
,
0
)
and
(
0
,
3
)
.
So, centre must be in second quadrant or fourth quadrant.
The
x
-coordinate of centre is negative.
∴
x
2
+
y
2
+
2
x
−
3
y
=
0
© examsnet.com
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