+y2=1 Now, equation of tangent in parametric form is ‌
x
√2
‌cos‌θ+ysin‌θ=1 Now, coordinate of X-intercept =(√2secθ,0)A Coordinate of Y-intercept =(0,cosec‌θ)B Let P(h,k) be the points which is the mid-points of A and B. h‌=‌
√2secθ
2
‌ and ‌k=‌
cosec‌θ
2
secθ‌=√2h‌ and ‌cosec‌θ=2k cos‌θ‌=‌