f(x)=x4−17x3+kx2−247x+210 Its factor: x2−5x+6 ∵(x−2)(x−3) is also a factor. ‌f(2)=16−17(8)+k(4)−(247)2+210=0 ‌⇒‌‌16−136+4k−494+210=0 ‌⇒‌‌4k−404=0⇒k=101 ‌∵f(x)=x4−17x3+101x2−247x+210 ‌‌‌=(x2−5x+6)(x2−12x+35)