Given that, ‌‌‌P(A‌ wins ‌)=0.6 ‌P(A‌ loses ‌)=0.3 ‌P(‌ game draw ‌)=0.1 ‌P(‌ A win at least two game ‌) ‌⇒‌‌P(WWW)+P(WWL)+P(WLW) ‌‌‌+P(LWW)+P(WWD) ‌‌‌+P(DWW)+P(WDW) ‌=(0.6)3+3(0.6)2(0.3)+3(0.6)2(0.1) ‌=(0.6)2(0.6+0.9+0.3) ‌=0.36(1.8)=0.648=‌