Here Q is the inverse point of P(−1,1) with respect to the circle ‌x2+y2−2x+2y=0 ‌⇒‌‌(x−1)2+(y+1)2=2 Centre of circle O≡(1,−1) ‌∴‌‌OP⋅OQ=r2 ‌⇒OQ=‌
r2
OP
=‌
2
√(1+1)2+(−1−1)2
‌=‌
2
√8
=‌
1
√2
OP,OQ are collinear ∴ Slope of OP=−1 Q point lie on OPQ ∴‌‌