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AP EAPCET 23-Aug-2021 Shift 2 Paper
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© examsnet.com
Question : 6
Total: 160
What are the values of
(
x
,
y
,
z
,
t
)
where
3
[
x
y
z
t
]
=
[
x
6
−
1
2
t
]
+
[
4
x
+
y
z
+
t
3
]
=?
(
2
,
4
,
3
,
1
)
(
2
,
4
,
1
,
3
)
(
1
,
3
,
2
,
4
)
(
1
,
3
,
4
,
2
)
Validate
Solution:
3
[
x
y
z
t
]
=
[
x
6
−
1
2
t
]
+
[
4
x
+
y
z
+
t
3
]
[
3
x
3
y
3
z
3
t
]
=
[
x
+
4
6
+
x
+
y
−
1
+
z
+
t
2
t
+
3
]
On comparing two matrices are equal if their corresponding elements are equal
3
x
=
x
+
4
⇒
x
=
2
3
t
=
2
t
+
3
⇒
t
=
3
3
z
=
−
1
+
z
+
t
⇒
3
z
=
−
1
+
z
+
3
⇒
z
=
1
3
y
=
6
+
x
+
y
⇒
2
y
=
6
+
2
⇒
y
=
4
∴
(
x
,
y
,
z
,
t
)
=
(
2
,
4
,
1
,
3
)
© examsnet.com
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