AP EAPCET 23-Aug-2021 Shift 2 Paper

Given that, weight of block B=w
Coefficient of friction between block and table =µ Let the maximum weight of block A=wA
To keep the cord between block B and knot horizontal, block must remains in equilibrium.
Now, from FBD of knot and block B. we get
wA=T‌sin‌θ ...(i)
f=µw=T‌cos‌θ ...(ii)
By dividing Eq. (i) by Eq. (ii), we get

wA

µw

=

T‌sin‌θ

T‌cos‌θ

wA=µw‌tan‌θ