Equation of polar isT=0 ‌‌ i.e., ‌αx+y(−1)−4⋅‌
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(x+α) ‌‌‌−6⋅‌
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(y+(−1))−12=0 ‌⇒‌‌αx−y−2x−2α−3y+3−12=0 ‌⇒‌‌(α−2x−4y−2α−9=0‌‌‌⋅⋅⋅⋅⋅⋅⋅(i) But equation of polar isy=βgiven So, coefficient ofxmust be zero. i.e.α−2=0⇒α=2 Thus,0−4y−2×(2)−9=0(from Eq.(i))‌‌‌⋅⋅⋅⋅⋅⋅⋅(ii) ‌⇒‌‌−4y=13 ‌⇒‌‌y=‌