Equation of polar isT=0 ‌‌ i.e., ‌αx+y(−1)−4⋅‌
1
2
(x+α) ‌‌‌−6⋅‌
1
2
(y+(−1))−12=0 ‌⇒‌‌αx−y−2x−2α−3y+3−12=0 ‌⇒‌‌(α−2x−4y−2α−9=0‌‌‌⋅⋅⋅⋅⋅⋅⋅(i) But equation of polar isy=βgiven So, coefficient ofxmust be zero. i.e.α−2=0⇒α=2 Thus,0−4y−2×(2)−9=0(from Eq.(i))‌‌‌⋅⋅⋅⋅⋅⋅⋅(ii) ‌⇒‌‌−4y=13 ‌⇒‌‌y=‌
