⇒m2−3m+2=0 ⇒‌‌m‌=1,2 So, equation of tangent (put point (1,3) on y=mc+c ) y‌=x+c,y=2x+c ⇒‌‌y‌=x+2y=2x+1 to find coordinates of A and B, put the line on parabola. ‌(x+2)2=8x⇒x2−4x+4=0 ‌⇒‌‌x=2,−2 ‌‌ at ‌‌‌x=2,y=√8×2=4 So, ‌‌A=(2,4) and (2x+1)2=8x ‌⇒4x2−4x+1=0 ‌⇒x=‌
