The efficiency formula for a Carnot engine is:
η=1−‌Here,
T1 is the absolute temperature of the source, and
T2 is the absolute temperature of the sink.
The problem says the source is
25% hotter than the sink. That means:
T1=T2+0.25×T2=1.25T2Now, plug
T1=1.25T2 into the efficiency formula:
‌η=1−‌‌η=1−‌‌‌=‌So,
‌η=1−‌‌η=‌To change this to a percentage, multiply by
100% :
η=‌×100%=20%So, the engine's efficiency is
20%.