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AP EAPCET 24-Aug-2021 Shift 1 Paper

Section: Physics

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Question : 118 of 160

Marks: +1, -0

1\\ \text{amu}

is ______

$931\\ \text{KeV}$
$931\\ \text{eV}$
$931\\ \text{MeV}$
$9.31\\ \text{MeV}$

Solution:

Given that atomic mass

=1

amu

=1.66 \times 10^{-27}\\ \text{kg}

By using Einstein's equation of mass energy relation,

E=mc^{2}

where,

c=

speed of light

=3 \times 10^{8}\\ \text{m/s}

.

E=\left(1.66 \times 10^{-27}\right) \times \left(3 \times 10^{8}\right)^{2}\\ \text{J}

=1.494 \times 10^{-11}\\ \text{J}

We know,

1\\ \text{MeV}=1.6 \times 10^{-13}\\ \text{J}

1\\ \text{J}=\frac{1}{1.6} \times 10^{13}\\ \text{MeV}

Substituting the value, we get

E=1.494 \times 10^{-11} \times \frac{1}{1.6} \times 10^{13}\\ \text{MeV}

=931\\ \text{MeV}

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