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AP EAPCET 24-Aug-2021 Shift 2 Paper
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© examsnet.com
Question : 22
Total: 160
Given
sin
1
°
sin
x
°
sin
(
x
+
1
)
°
=
cot
x
°
−
cot
(
x
+
1
)
°
, then the value of
1
sin
45
°
sin
46
°
+
1
sin
46
°
sin
47
°
+
.
.
.
.
.
+
1
sin
89
°
sin
90
°
is
sin
1
°
cot
1
°
−
cot
1
°
cosec
1
°
Validate
Solution:
Given,
sin
l
*
sin
x
0
sin
(
x
+
1
)
*
=
cot
x
*
−
cot
(
x
′
′
+
1
)
1
sin
45
°
sin
46
°
+
1
sin
46
°
sin
47
°
+
.
.
.
+
1
sin
89
sin
90
°
=
1
sin
1
°
[
cot
45
°
−
cot
46
°
+
cot
46
°
−
cot
47
°
+
.
.
.
cot
89
°
−
cot
90
°
]
=
1
sin
l
°
[
cot
45
°
]
=
1
sin
l
°
=
cosec
1
°
© examsnet.com
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