We have, ∫4sinx+5cosx3cosx−2sinxdx=A(5cosx+4sinx)+Bx+c On differentiating both sides, we get 4sinx+5cosx3cosx−2sinx=4sinx+5cosxA(−5sinx+4cosx)+B⇒4sinx+5cosx3cosx−2sinx
=4sinx+5cosx−5Asinx+4Acosx+4Bsinx+5Bcosx
⇒3cosx−2sinx=(4B−5A)sinx+(5B+4A)cosx
Equating the coefficient of cosx and sinx, we get 5B+4A=3 and 5A−4B=2 Solving, we get A=4122 and B=417