From graph, the force is varying sinusoidally with time by equation, F=−2.cosωt ...(i) where, ω be the angular frequency of variation of force. Since, the graph is completing one cycle in 8s, hence time period, T=8s Using expression of change of momentum. Δn=∫n8Fdt=∫n8−2cosωtdt [from Eq. (i)] =−
2
ω
[sinωt]38 =
−2
ω
[sinω8−sin0] =
−2
ω
[sin
2π
8
8−0](∵ω=
2π
T
) =
−2
ω
[sin2π]=0[∵sin0=sin2π=0] Hence, the gain or change of linear momentum is zero.