P Block Elements

Let's look at the reaction step by step.Aluminium carbide, typically represented as $\mathrm{Al}_4\mathrm{C}_3$, reacts with water to produce aluminium hydroxide and methane. The balanced reaction with $\mathrm{H}_2\mathrm{O}$ is:$\mathrm{Al}_4\mathrm{C}_3+12\mathrm{H}_2\mathrm{O}\longrightarrow4\mathrm{Al}(\mathrm{OH})_3+3\mathrm{CH}_4 .$When deuterium oxide ( $\mathrm{D}_2\mathrm{O}$ ) is used instead of water, every hydrogen atom is replaced by deuterium. Hence, aluminium hydroxide becomes aluminium deuteroxide, $\mathrm{Al}(\mathrm{OD})_3$, and methane becomes fully deuterated methane, $\mathrm{CD}_4$.The modified reaction becomes:$\mathrm{Al}_4\mathrm{C}_3+12\mathrm{D}_2\mathrm{O}\longrightarrow4\mathrm{Al}(\mathrm{OD})_3+3\mathrm{CD}_4 .$So, the product $X^{\prime}$ in the reaction is $\mathrm{CD}_4$.Thus, the correct answer is Option D: $\mathrm{CD}_4$.