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Differentiation
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Section:
Mathematics
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© examsnet.com
Question : 11 of 34
Marks:
+1
,
-0
If
x
=
2
cos
3
θ
and
y
=
3
s
i
n
2
θ
, then
d
y
d
x
=
[AP EAPCET 22 May 2025 S1]
−
s
e
c
θ
cos
θ
−
cosec
θ
s
i
n
θ
Validate
Solution:
x
=
2
cos
3
θ
,
˙
y
=
3
s
i
n
2
θ
⇒
d
x
d
y
=
d
x
d
θ
d
y
d
θ
⇒
d
x
d
y
=
6
cos
2
θ
(
−
s
i
n
θ
)
6
s
i
n
θ
(
cos
θ
)
⇒
d
y
d
x
=
−
s
e
c
θ
© examsnet.com
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