Test Index

Rotational Motion

Section: Physics

© examsnet.com

Question : 24 of 24

Marks: +1, -0

The moments of inertia of a solid cylinder and a hollow cylinder of same mass and same radius about the axes of the cylinders are

I_1

I_2

. The relation between

I_1

I_2

[AP EAPCET 18 May 2024 Shift 1]

$\; I_1 < I_2$
$\; I_1 = I_2$
$\; I_1 > I_2$
$\; I_1 = I_2 = 0$

Solution:

Mass of both cylinders

=M

Radius of both cylinders

=R

The moment of inertia for a solid cylinder and a hollow cylinder about their axes are as follows:

For the solid cylinder:

I_1=\;\frac{M R^2}{2}

For the hollow cylinder:

I_2=M R^2

From these formulas, it is clear that:

I_1 < I_2

© examsnet.com

Go to Question:

Prev Question