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AP ICET 2016 Paper
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© examsnet.com
Question : 107
Total: 200
A person A having completed 60% of the work in 15 days, calls another person B and they together finish the remaining work in 5 days. Then how many days B alone would have taken to do the whole work?
25
20
37
1
2
37
Validate
Solution:
60% work ≡ 15 days
∴ 100% work
≡
15
×
100
60
=
25
days
⇒ A alone can do the work in 25 days
Remaining work = 40%
=
2
5
Let B alone do the work in x days.
⇒
5
(
1
25
+
1
x
)
=
2
5
⇒
1
x
=
2
25
−
1
25
=
1
25
⇒
x
=
25
days
Aliter
Remaining 40 % work is done by A + B in 5 days
∴ A + B will do 60% work in
5
×
60
40
=
15
2
A alone does 60% work in 15 days
⇒ A and B are equally efficient
∴ Time taken by B or A alone to do 100% work
=
15
×
100
60.
=
25
days
© examsnet.com
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