Now, the 2 vowels can occupy the 5 places (marked by rectangular boxes). Itcan be done in ^5P_2=20 ways.
Total 6 letters of WISDOM can be arranged in 6! ways.
∴ Required probability ={4!\times^5P_2}/6!=20/{6\times5}=2/3" >
WISDOM has 2 vowels Let us first arrange the 4 consonants which can be done in 4! ways
Now, the 2 vowels can occupy the 5 places (marked by rectangular boxes). Itcan be done in 5P2=20 ways. Total 6 letters of WISDOM can be arranged in 6! ways. ∴ Required probability =