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AP ICET 2016 Paper

Question : 143 of 200

Marks: +1, -0

Solution:

WISDOM has 2 vowels

Let us first arrange the 4 consonants which can be done in 4! ways

Now, the 2 vowels can occupy the 5 places (marked by rectangular boxes). Itcan be done in

{}^5P_2 = 20

ways.

Total 6 letters of WISDOM can be arranged in 6! ways.

∴ Required probability

= \frac{4! \times {}^5P_2}{6!} = \frac{20}{6 \times 5} = \frac{2}{3}

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