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BITSAT 2005 Solved Question Paper
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© examsnet.com
Question : 9
Total: 150
If
θ
is an acute angle and
sin
θ
2
=
√
x
−
1
2
x
, then
tan
θ
is equal to :
x
2
−
1
√
x
2
−
1
√
x
2
+
1
x
2
+
1
Validate
Solution:
Given that
sin
θ
2
=
√
x
−
1
2
x
In
Δ
A
B
C
tan
θ
2
=
√
x
−
1
x
+
1
∴
tan
θ
=
2
tan
θ
2
1
−
tan
2
θ
2
=
2
√
x
−
1
x
+
1
1
−
x
−
1
x
+
1
=
2
√
x
−
1
x
+
1
2
x
+
1
=
√
x
2
−
1
© examsnet.com
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