If given vectors are coplanar, then there exists two scalar quantities x and y such that 2i^−j^+k^ = x (i^+2j^−3k^) + y (3i^+aj^+5k^) ... (1) Comparing coefficient of i^,j^ and k^ on both sides of (1) we get x + 3y = 2 , 2x + ay = –1 , –3x + 5y = 1 ...(2) Solving first and third equations, we get x = 1/2, y = 1/2 Since the vectors are coplanar, therefore these values of x and y will satisfy the equation 2x + ay = –1 ∴ 2 (1/2) + a (1/2) = – 1 ⇒ a = –4