Test Index

BITSAT 2013 Paper

Section: Chemistry

Question : 58 of 150

Marks: +1, -0

RCOOK $\xrightarrow[Ocidation]{Electrolytic}$
$\mathrm{RCOO}^{-} \mathrm{Ag}^{+}$ $\xrightarrow{\mathrm{Br}_2}$
$\mathrm{CH}_3\mathrm{CH}_3$ $\xrightarrow[h\nu]{\mathrm{Cl}_2}$
$(\mathrm{CH}_3)_3\mathrm{CCl}$ $\xrightarrow{\mathrm{C}_2\mathrm{H}_5\mathrm{OH}}$

Solution:

Electrolysis of a concentrated aqueous solution of either sodium or potassium salts of saturated carboxylic acids yields higher alkane at anode.

RCOOK

\xrightarrow[Ocidation]{Electrolytic}

2RCO^{-}_{\text{Anode}}

2K^{+}_{\text{Cahode}}

At anode

2RCOO^{-}

→ 2RCOO +

2e^{-}

→ R - R +

2\mathrm{CO}_2

At Cathode

2K^{+} + 2e^{-}

→ 2K

2K +

\mathrm{H}_2\mathrm{O}

→

2\mathrm{KOH} + \mathrm{H}_2

↑

(Kolbe's Method)

Go to Question:

Prev Question

Next Question