Test Index

BITSAT 2014 Paper

Section: Physics

Question : 25 of 150

Marks: +1, -0

Solution:

Since, the radius of circular path of a charged particle in magnetic field is r =

\frac{mv}{qB}

\frac{\rho}{qB}

Now, the radius of circular path of charged particle of given momentum r and magnetic field B is given by

r α

\frac{1}{q}

But charge on both charged particles, protons and deuterons, is same. Therefore,

\frac{r_{\rho}}{r_{D}}

\frac{q_{D}}{q_{\rho}}

\frac{1}{1}

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