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BITSAT 2014 Paper

Section: Physics

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Question : 38 of 150

Marks: +1, -0

Let binding energy per nucleon of nucleus is denoted by

E_{bn}

and radius of nucleus is denoted as r. If mass number of nuclei A, B and 64 and 125 respectively then

$r_A$ < $r_B$ , $E_{bnA}$ < $E_{bnB}$
$r_A$ > $r_B$ , $E_{bnA}$ > $E_{bnB}$
$r_A$ = $\frac{4}{5} r_B$ , $E_{bnA}$ < $E_{bnB}$
$r_A$ < $r_B$ , $E_{bnA}$ > $E_{bnB}$

Solution:

r =

r_0(a)^{1/3}

r increases with increasing A mass number

So,

r_A

<

r_B

as mass number of A is smaller

E_{bn}

decreases with increasing A for A > 56,

{}^{56}\mathrm{Fe}

has highest

E_{bn}

value.

So,

E_{bn}

for A = 64 is larger as compared to

E_{bn}

for nucleus with A = 125

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