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BITSAT 2014 Paper
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© examsnet.com
Question : 44
Total: 150
The enthalpy of sublimation of aluminium is 330 kJ/mol. Its Ist, IInd and IIIrd ionization enthalpies are 580, 1820 and 2740 kJ respectively. How much heat has too be supplied (in kJ) to convert 13.5 g of aluminium into
A
l
3
+
ions and electrons at 298 k
5470
2735
4105
3765
Validate
Solution:
Heat needed too be supplied per mol = 330 + 580 + 1820 + 2740 = 5470 kJ
No. of mols of Al taken =
113.5
27
= 0.5 mol
Heat required = 0.5 × 5470 kJ = 2735 kJ
© examsnet.com
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