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BITSAT 2014 Paper

Section: Physics

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Question : 5 of 150

Marks: +1, -0

A person with his hand in his pocket is skating on ice at the rate of 10m/s and describes a circle of radius 50 m. What is his inclination to vertical: (g = 10 m/

\sec^2

$\tan^{-1}\left(\frac{1}{2}\right)$
$\tan^{-1}\left(\frac{1}{5}\right)$
$\tan^{-1}\left(\frac{3}{5}\right)$
$\tan^{-1}\left(\frac{1}{10}\right)$

Solution:

Since surface (ice) is frictionless, so the centripetal force required for skating will be provided by inclination of boy with the vertical and that angle is given as tan θ =

\frac{v^2}{rg}

where v is speed of skating & r is radius of circle in which he moves

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