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BITSAT 2014 Paper

Section: Chemistry

Question : 57 of 150

Marks: +1, -0

m^3

Solution:

The packing efficiency = 0.68, means the given lattice is BCC.

The closest distance of approach = 2r

2r = 2.86

\overset{0}{A}

= The packing efficiency = 0.68, means thegiven lattice is BCC.The closest distance of approach =

2\sqrt{3}

or a =

\frac{2\times 2.86}{\sqrt{3}}

= 3.30

\overset{0}{A}

Let atomic weight of the element = a

∴

\frac{2\times 9}{36\times 10^{23}\times (3.3)^3\times 10^{-24}}

= 8.57

a = 8.57 × 3 ×

(3.3)^3

× 0.1

= 92.39 ~ 93 amu

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