Given x+2y≥2.....(1) x+2y≤8....(2) and x,y≥0
From equation (1)
x
2
+
y
1
=1 and for equation (2)
x
8
+
y
4
=1 Given : z=3x+2y At point (2,0);z=3×2+0=6 At point (0,1);z=3×0+2×1=2 At point(8,0);z=3×8+2×0 = 24 At point (0,4);z=3×0+2×4=8 ∴ maximum value of z is 24 at point (8,0).