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BITSAT 2017 Slot 2 Solved Paper
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© examsnet.com
Question : 148
Total: 150
If
∫
(
√
x
)
5
d
x
(
√
x
)
7
+
x
6
=
λ
log
(
x
9
x
9
+
1
)
+
C
, then
a
+
λ
equal to
2
>
2
<
2
>
3
Validate
Solution:
Let
I
=
∫
d
x
(
√
x
)
2
+
(
√
x
)
7
=
∫
d
x
(
√
x
)
7
(
1
(
√
x
)
5
+
1
)
Put
1
+
1
(
√
x
)
5
=
t
⇒
−
5
2
.
1
(
√
x
)
7
d
x
=
d
t
∴
I
=
−
2
5
∫
d
t
t
=
−
2
5
log
t
+
C
=
−
2
5
log
[
1
+
1
(
√
x
)
5
]
+
C
=
−
2
5
log
(
x
5
∕
2
+
1
x
5
∕
2
)
+
C
⇒
λ
=
−
2
5
and
a
=
5
2
∴
a
+
λ
=
2.1
>
2
© examsnet.com
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