Using Einstein’s photoelectric equations, hv=ϕ+eVs eVs=hv−ϕ .......(i) Thus, when the frequency of incident light radiation (photons) v increases to 2v, the stopping potential Vs changes to V′s. eV′s=h(2v)−ϕ .......(ii) On dividing Eq. (ii) by Eq. (ii), we get