BITSAT 2019 Paper

(a) Since A moves twice the distance moved by B. If acceleration of B is ‘a’, then acceleration of A is ‘2a’. T' - (T +T) = 0 (since pulley is massless) ⇒ T' = 2T ....(i)For 5 kg block5g - T' = 5afor 2 kg block⇒ 5g - 2T = 5a ....(ii) [ T’ = 2T ]T = 2 x (2a) = 4a ....(iii)From equations (ii) and (iii),5g - (2 × 4a) = 5a5g - 8a = 5a5g = 13a a = $\frac{5}{13}$ ga $_{A}$ = 2a = $\frac{10}{13}$ g ; a $_{B}$ = a = $\frac{5}{13}$ g