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BITSAT 2019 Slot 2 Solved Paper
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© examsnet.com
Question : 34
Total: 150
Frequency of oscillation of a body is
5
H
z
when a force
F
1
is applied and
12
H
z
when another force
F
2
is applied. If both forces
F
1
and
F
2
are applied together, then frequency of oscillation of the body will be
13 Hz
169 Hz
62 Hz
52 Hz
Validate
Solution:
According to the question,
F
1
=
−
k
1
x
and
F
2
=
−
k
2
x
∴
Frequency of oscillation
v
1
=
1
2
π
√
k
1
m
5
=
1
2
π
√
k
1
m
⇒
k
1
=
100
π
2
m
Similarly,
12
=
1
2
π
√
k
2
m
⇒
k
2
=
576
π
2
m
Now,
F
=
F
1
+
F
2
=
−
(
k
1
+
k
2
)
x
∴
Frequency of oscillation,
v
=
1
2
π
√
k
1
+
k
2
m
=
1
2
π
√
100
π
2
m
+
576
π
2
m
m
⇒
v
=
13
H
z
© examsnet.com
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