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BITSAT 2021 Paper
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Section:
Mathematics
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© examsnet.com
Question : 122
Total: 150
If
x
=
1
−
t
2
1
+
t
2
and
y
=
2
t
1
+
t
2
, then
dy
dx
is equal to :
−
y
x
y
x
−
x
y
x
y
Validate
Solution:
Let
x
=
1
−
t
2
1
+
t
2
and
y
=
2
t
1
+
t
2
Put
t
=
tan
θ
, we get
x
=
1
−
tan
2
θ
1
+
tan
2
θ
and
y
=
2
tan
θ
1
+
tan
2
θ
⇒
x
=
cos
2
θ
and
y
=
sin
2
θ
∴
dx
d
θ
=
−
2
sin
2
θ
and
dy
d
θ
=
2
cos
2
θ
Now,
dy
dx
=
dy
d
θ
×
d
θ
dx
=
−
cos
2
θ
sin
2
θ
=
−
x
y
© examsnet.com
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