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BITSAT 2022 Paper
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Section:
Mathematics
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© examsnet.com
Question : 100
Total: 130
If
x
∈
(
0
,
π
2
)
, then the value of
cos
−
1
(
7
2
(
1
+
cos
2
x
)
+
√
(
s
i
n
2
x
−
48
cos
2
x
)
s
i
n
x
)
is equal to
x
−
cos
−
1
(
7
cos
x
)
x
+
s
i
n
−
1
(
7
cos
x
)
x
+
cos
−
1
(
6
cos
x
)
x
+
cos
−
1
(
7
cos
x
)
Validate
Solution:
👈: Video Solution
y
=
c
o
s
−
1
(
7
2
(
1
+
c
o
s
2
x
)
+
√
(
s
i
n
2
x
−
48
c
o
s
2
x
)
s
i
n
x
)
=
c
o
s
−
1
(
(
7
c
o
s
x
)
(
c
o
s
x
)
+
√
1
−
49
c
o
s
2
x
√
1
−
c
o
s
2
x
)
=
c
o
s
−
1
(
c
o
s
x
)
−
c
o
s
−
1
(
7
c
o
s
x
)
[
∵
c
o
s
x
<
7
c
o
s
x
]
=
x
−
c
o
s
−
1
(
7
c
o
s
x
)
© examsnet.com
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