Given, first resonance column at deoth, l1=24 cm Second resonance column at depth, l2=78 cm Third resonance column at depth, l3=?As l1+x=4λ=24...............(i)l2+x=43λ=78................(ii)l3+x=45λ................(iii) From Eqs. (i) and (ii), x=2l2−3l1=278−3(24)=3..................(iv) substituting l1 and x value, we get l3=5(24)+4(3)⇒l3=132 cm.