Test Index

BITSAT 2022 Paper

Section: Logical Reasoning

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Question : 77 of 130

Marks: +1, -0

The average marks of 50 students in a class was found to be 64 . If the marks of two students were incorrectly entered as 38 and 42 instead of 83 and 24 , respectively, then what is the correct average?

$64.54$
$62.32$
$61.24$
$61.86$

Solution:

Average marks of 50 students

= 64

Sum of marks of 50 students

=

Average

\times

number of students

=64\times50=3200

According to the question,

Correct sum of marks of

50

students

=3200-38-42+83+24

=3200+27

=3227

\therefore

Correct average marks of

50

students

=\frac{3227}{50} = 64.54

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