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BITSAT 2023 Shift 2 Solved Paper

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Question : 104

Total: 130

∫tan−1√x‌dx is equal to

(x+1)tan−1√x−√x+C
xtan−1√x−√x+C
√x−xtan−1√x+C
√x−(x+1)tan−1√x+C

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