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BITSAT 2023 Shift 2 Solved Paper
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© examsnet.com
Question : 114
Total: 130
If
A
and
B
are mutually exclusive events and if
P
(
B
)
=
1
3
,
P
(
A
∪
B
)
=
13
21
, then
P
(
A
)
is equal to
1
∕
7
4
∕
7
2
∕
7
5
∕
7
Validate
Solution:
👈: Video Solution
For mutually exclusive events
P
(
A
∪
B
)
=
P
(
A
)
+
P
(
B
)
⇒
P
(
A
)
=
2
7
© examsnet.com
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