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BITSAT 2023 Shift 2 Solved Paper
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© examsnet.com
Question : 12
Total: 130
Two resistances are given as
R
1
=
(
10
±
0.5
)
Ω
and
R
2
=
(
15
±
0.5
)
Ω
. The percentage error in the measurement of equivalent resistance when they are connected in parallel is
6.33
2.33
4.33
5.33
Validate
Solution:
👈: Video Solution
Equivalent resistance in parallel combination is given by
1
R
e
q
=
1
R
1
+
1
R
2
⇒
R
eq
=
R
1
R
2
R
1
+
R
2
=
10
×
15
10
+
15
=
6
Differentiating both sides, we get
∆
R
e
q
R
e
q
2
=
∆
R
1
R
1
2
+
∆
R
2
R
2
2
⇒
∆
R
e
q
R
e
q
=
(
∆
R
1
R
1
2
+
∆
R
2
R
2
2
)
R
e
q
=
(
0.5
100
+
0.5
225
)
6
=
(
6
×
0.5
25
)
(
1
4
+
1
9
)
=
13
300
∆
R
e
q
R
e
q
×
100
=
13
3
=
4.33
%
© examsnet.com
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