BITSAT 2024 Shift 1 Paper

To find the average value of the current from $t=0$ to $t=2$ seconds, we analyze the current-time $(i-t)$ graph.Calculate the Area under the Graph:The graph consists of two triangular sections.First Triangle: From $t=0$ to $t=1$ second, with a height of 10 A .Area of first triangle $=\;\frac{1}{2} \times$ base $\times$ height $=\;\frac{1}{2} \times 1 \times 10 = 5\ \text{A}$Second Triangle: From $t=1$ to $t=2$ seconds, with a height of 10 A .Area of second triangle $=\;\frac{1}{2} \times (2-1) \times 10 = 5\ \text{A}$Total Area:Total area under the graph from $t=0$ to $t=2$ seconds is:$5\ \text{A} + 5\ \text{A} = 10\ \text{A}$Calculate the Average Current:The average current ( $i_{\text{av}}$ ) is given by:$i_{\text{av}} = \;\frac{\;\text{ Total Area }\;}{\;\text{ Time Interval }\;} = \;\frac{10}{2} = 5\ \text{A}$Thus, the average current over the interval from $t=0$ to $t=2$ seconds is 5 A .