What is the energy released by fission of 1 {g} of {U}²35} ?

Correct Answer is : 2.26104kWh2.2610^{4} {kWh}2.26104kWh

Correct Answer is : 2.26104kWh2.2610^{4} {kWh}2.26104kWh

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BSc Nursing GNM 2019 Solved Paper

Question : 22 of 200

Marks: +1, -0

1 \text{g}

\mathrm{U}^{235}

Solution:

Energy released in one fission of

{}_{92}^{235}\mathrm{U}

nucleus

=200 \text{MeV}

Mass of uranium

=1 \text{g}

We know that,

235 \text{g}

{}^{235}\mathrm{U}

has

6.023 \times 10^{23}

atoms or nuclei.

\therefore

Energy released in fission of

1 \text{g}

\mathrm{U}^{235}

E\;\;=\;\frac{6.023 \times 10^{23} \times 1 \times 200}{235}

\;\;=5.1 \times 10^{23} \text{MeV}

\;\;=5.1 \times 10^{23} \times 1.6 \times 10^{-13} \text{J}

=\;\frac{5.1 \times 10^{23} \times 16 \times 10^{-13}}{3.6 \times 10^{6}} \text{kWh}

=2.26 \times 10^{4} \text{kWh}

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