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CAT 2015 Quantitative Ability
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© examsnet.com
Question : 16
Total: 34
Three persons - A, B and C - are playing the game of death. 3 bullets are placed randomly in a revolver having 6 chambers. Each one has to shoot himself by pulling the trigger once after which the revolver passes to the next person. This process continues till two of them are dead and the survivor of the game becomes the winner What is the probability that B is the winner if A starts the game and A. B and C take turns in that order.
0 33
0.3
0.25
None of these
Validate
Solution:
Total number of the cases =
6
C
3
=
20
The favourable cases for B surviving are: (B : Bullet; N : No Bullet)
BNBBNN or
BNBNBN or
BNBNNB or
BNNNBB or
NNBBNB or
NNBBBN.
Hence probability = 6/20 = 0.3
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