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CAT 2016 Quantitative Ability
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© examsnet.com
Question : 13
Total: 34
An unsharpened cylindrical pencil consists of a layer of wood surrounding a solid cylinder of graphite. The radius of a pencil is 7 mm, the radius of the graphite cylinder is 1 mm and the length of the pencil is 10 cm. Find the cost of the material used in a pencil, if the cost of wood is
Rs
.0
.70
∕
cm
3
and that of graphite is
Rs
.2
.10
∕
cm
3
.
Rs.8.76
Rs.10.02
Rs.11.22
Rs. 13.74
Validate
Solution:
Volume of a cylinder =
π
r
2
h
, where
r = radius of the cylinder
h = height of the cylinder
Volume of the graphite cylinder
=
π
(
1
10
)
2
×
10
=
π
10
c
m
3
Volume of the layer of wood
=
10
π
[
(
7
10
)
2
−
(
1
10
)
2
]
=
48
π
10
c
m
3
Cost of the material in a pencil
=
π
10
×
2.10
+
48
π
10
×
0.70
= Rs. 11.22
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