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CAT 2016 Quantitative Ability
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© examsnet.com
Question : 16
Total: 34
Find the minimum possible value of 'y' if
4
7
<
x
y
<
12
13
,
where x and y are natural numbers
4
5
3
2
Validate
Solution:
4
7
<
x
y
<
12
13
,
⇒
13
x
12
<
y
<
7
x
4
As ‘x’ increases, the interval in which ‘y‘ lies alsoincreases.
For x = 1, the intervals in which y lies is
(
1
1
12
,
1
3
4
)
This interval does not contain any integer.
For x = 2, the interval in which y lies is
(
2
1
6
,
3
1
2
)
and 3 lies in the interval.
Hence, the minimum possible value of y is 3.
© examsnet.com
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