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CAT 2019 Shift 1 Paper
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© examsnet.com
Question : 69
Total: 100
If
a
1
+
a
2
+
a
3
+
.
.
.
+
a
n
=
3
(
2
n
+
1
−
2
)
,
for every n ≥ 1, then
a
11
equals
Your Answer:
Validate
Solution:
If
n
=
1
,
a
1
=
3
(
2
1
+
1
−
2
)
=
6
=
3
×
2
1
If
n
=
2
,
a
1
+
a
2
=
3
(
2
2
+
1
−
2
)
=
18
⇒
a
2
=
18
−
a
1
=
12
=
3
×
2
2
If
n
=
3
,
a
1
+
a
2
+
a
3
=
3
(
2
3
+
1
−
2
)
=
42
⇒
a
3
=
42
−
(
a
1
+
a
2
)
=
24
=
3
×
2
3
Following the pattern,
a
n
=
3
×
2
n
Therefore,
a
11
=
3
×
2
11
=
6144
© examsnet.com
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