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CAT 2020 Exam Shift 1 Solved Paper
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© examsnet.com
Question : 69
Total: 76
If
a
,
b
and
c
are positive integers such that
a
b
=
432
,
b
c
=
96
and
c
<
9
, then the smallest possible value of
a
+
b
+
c
is
56
59
49
46
Validate
Solution:
Given
a
b
=
432
,
b
c
=
96
and
c
<
9
To find the minimum value for
a
+
b
+
c
, the two larger numbers should be as close as possible.
The closest combination whose product is 432 is
18
×
24
. For
b
=
24
, we get
c
=
4
and
a
=
18
Hence the least value for
a
+
b
+
c
=
46
.
© examsnet.com
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