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CAT 2020 Exam Shift 2 Solved Paper
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© examsnet.com
Question : 55
Total: 76
Let the
m
-th and
n
-th terms of a geometric progression be
3
4
and 12 , respectively, where $m
−
2
2
6
−
4
Validate
Solution:
T
n
=
12
T
m
=
3
∕
4
T
n
T
m
=
a
r
n
−
1
a
r
m
−
1
=
12
3
4
r
n
−
m
=
16
=
(
±
2
)
4
=
(
±
4
)
2
To get the minimum value for
r
+
n
−
m
,
r
should be minimum.
∴
r
=
−
4
n
−
m
=
2
∴
Required answer
=
−
2
© examsnet.com
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